|vec(a)|=2 , |vec(b)|=3 (vec(a)−vec(b)) perpendicular (6vec(a) +vec(b)) 6vec(a)^2−5vec(a)vec(b) −vec(b)^2=0 12−5vec(a) vec(b) −3=0 5(6cos theta)=9 But the answer is (pi)/(3). Where am i wrong?

oopsteekwe

oopsteekwe

Answered question

2022-10-31

( a b ) perpendicular ( 6 a + b )
6 a 2 5 a b b 2 = 0
12 5 a b 3 = 0
5 ( 6 cos θ ) = 9
But the answer is π 3 . Where am i wrong?

Answer & Explanation

Kaylee Evans

Kaylee Evans

Beginner2022-11-01Added 20 answers

v v = v 2 . You used v instead.

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