A farmer sells corn for $6.00/bu and soybeans for $15.00/bu. The entire 3150 bu sells for $22,950. How much of each is sold?

DofotheroU

DofotheroU

Answered question

2021-03-07

A farmer sells corn for $6.00/bu and soybeans for $15.00/bu. The entire 3150 bu sells for $22,950. How much of each is sold?

Answer & Explanation

SkladanH

SkladanH

Skilled2021-03-08Added 80 answers

Let x be the number of bushels of corns and y be the number of bushels of soybeans.
There is a total of 3150 bushels:
x+y=3150
The total amount sold is $22950:
6x+15y = 22950
Solve for y using (1) to obtain (3): y=3150-x
Substitute (3) to (2) and solve for x: 6x+15(3150x)=22950
6x + 47250 — 15x = 22950
9x+47250=22950
9x=24300
x=2700
Solve for y using (3):
y = 3150-2700
y= 450
So. 2700 bushels of corn and 450 bushels of soybeans were sold.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-08-10Added 2605 answers

Answer is given below

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?