Let x be the number of bushels of corns and y be the number of bushels of soybeans.

There is a total of 3150 bushels:

x+y=3150

The total amount sold is $22950:

6x+15y = 22950

Solve for y using (1) to obtain (3): y=3150-x

Substitute (3) to (2) and solve for x: \(\displaystyle{6}{x}+{15}{\left({3150}—{x}\right)}={22950}\)

6x + 47250 — 15x = 22950ZSK

\(\displaystyle—{9}{x}+{47250}={22950}\)

\(\displaystyle-{9}{x}=—{24300}\)

x=2700

Solve for y using (3):

y = 3150-2700

y= 450

So. 2700 bushels of corn and 450 bushels of soybeans were sold.

There is a total of 3150 bushels:

x+y=3150

The total amount sold is $22950:

6x+15y = 22950

Solve for y using (1) to obtain (3): y=3150-x

Substitute (3) to (2) and solve for x: \(\displaystyle{6}{x}+{15}{\left({3150}—{x}\right)}={22950}\)

6x + 47250 — 15x = 22950ZSK

\(\displaystyle—{9}{x}+{47250}={22950}\)

\(\displaystyle-{9}{x}=—{24300}\)

x=2700

Solve for y using (3):

y = 3150-2700

y= 450

So. 2700 bushels of corn and 450 bushels of soybeans were sold.