Nine batteries are hooked in series to provide a 33-V power source. Some of the batteries are 3 V and some are 4.5 V. How many of each type are used?

Maiclubk

Maiclubk

Answered question

2021-03-08

Nine batteries are hooked in series to provide a 33-V power source. Some of the batteries are 3 V and some are 4.5 V. How many of each type are used?

Answer & Explanation

Daphne Broadhurst

Daphne Broadhurst

Skilled2021-03-09Added 109 answers

There is a total of 9 batteries: x+y=9
Since the batteries are in series, the total amount of voltage 33V is the sum of the individual voltages of the batteries: 3x+4.5y=33
Solve for y using (1) to obtain (3): y=9-x
Substitute (3) to (2) and solve for x: 3x+4.5(9-x)=33
3x+40.5-4.5x=33
-1.5x+40.5=33
-1.5x=-7.5
x=5
Solve for y using (3): y=9-5
y=4
So, there were 5 3V batteries and 4 4.5V batteries.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?