If Jeremy has 4 times as many dimes as nickels and they have a combined value of 360 cents, how many of each coin does he have?

Question
If Jeremy has 4 times as many dimes as nickels and they have a combined value of 360 cents, how many of each coin does he have?

Answers (1)

2021-02-22
Let d be the number of dimes and n be the number of nickels. Jeremy has 4 times as many dimes as nickels:
d=4n
The combined value of 360 cents (Recall: 1 dime = 10 cents, 1 nickel = 5 cents)
10d+5n=360
Solve by subtitution. Substitute (1) to (2) and solve for n: 10(4n)+5n=360
40n+5n=360
45n=360
n=8
Solve for d using (1): d=4(8)
d=32
So, Jeremy has 32 dimes and 8 nickels.
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