Let d be the number of dimes and n be the number of nickels.
Jeremy has 4 times as many dimes as nickels:

d=4n

The combined value of 360 cents (Recall: 1 dime = 10 cents, 1 nickel = 5 cents)

10d+5n=360

Solve by subtitution. Substitute (1) to (2) and solve for n: 10(4n)+5n=360

40n+5n=360

45n=360

n=8

Solve for d using (1): d=4(8)

d=32

So, Jeremy has 32 dimes and 8 nickels.

d=4n

The combined value of 360 cents (Recall: 1 dime = 10 cents, 1 nickel = 5 cents)

10d+5n=360

Solve by subtitution. Substitute (1) to (2) and solve for n: 10(4n)+5n=360

40n+5n=360

45n=360

n=8

Solve for d using (1): d=4(8)

d=32

So, Jeremy has 32 dimes and 8 nickels.