A triangle ABC is drawn (angle C=90^circ), in which CL (L in AB) is bisector. The circle k with diameter CL intersects AB, BC and CA, respectively, in M, N and P. Show that MN and MP are angle bisectors of angle BMC and angle AMC.

Keyla Koch

Keyla Koch

Answered question

2022-10-27

Show that MN and MP are angle bisectors
A A B C is drawn ( C = 90 ), in which CL ( L A B ) is bisector. The circle k with diameter CL intersects AB, BC and CA, respectively, in M, N and P. Show that MN and MP are angle bisectors of B M C and A M C.

Answer & Explanation

canhaulatlt

canhaulatlt

Beginner2022-10-28Added 17 answers

Step 1
C M B = C M A = 90 , since C M L subtends the diameter CL.
By the inscribed angle theorem, L P C = 90 = L N C
Triangles LPC and LNC are equal (by common side and equal angles), so C P = C N and CPN is an isosceles right triangle.
Step 2
By the inscribed angle theorem, C M P = C N P = 45 , so MP is the angle bisector of C M A.
Analogically, MN is the angle bisector of C M B.

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