An insulated, constant-volume system containing 1.36 kg of air receives 53 kJ of paddle work. The initial temperature is 27°C. Determine a) the change of internal energy. b) the final temperature. Assume a mean value C. = 0.718 kJ/kgK.

oopsteekwe 2022-10-26 Answered
An insulated, constant-volume system containing 1.36 kg of air receives 53 kJ of paddle work. The initial temperature is 27 C. Determine a) the change of internal energy. b) the final temperature. Assume a mean value C. = 0.718 kJ/kgK.
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Answers (1)

Sauppypefpg
Answered 2022-10-27 Author has 23 answers
Given Initial temperature T 1 = 27 C = 27 + 273 = 300   K
mass m = 1.36
Work done W =−53 kJ (since it is externally input work)
Let T 2 be the final temperature
C V = 0.718  kJ/Kg K
From the first law of thermodynamics
dU= dQ− W
It is an insulated system no heat transfer takes placeso
dQ = 0dU =− WdU = 53 kJdU
is the change in internal energy. We know that Change in internal energy is given by dU = mCvdT
53 = 1.36 0.718 ( T 2 T 1 ) 53 = 0.97648 ( T 2 300 ) 54.2766 = T 2 300 T 2 = 345.2766   K = 81.2766 C
a) the final temperature = 81.266 degree celsius
b) Change in internal energy dU = 53 kJ
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