re-arrange equation $L={2}^{10(v-1)}{v}^{2}$

Is it possible to re-arrange this equation to make v the subject?

$$L={v}^{2}.{2}^{10(v-1)}$$

If so, what is the answer?

If it helps (which by excluding zero it should)...

$$0<v<1$$

I have tried pages of scribbling and got nowhere. In desperation I have tried solving each product separately (easy enough), and then tried to get the right overall result from some combination of $$\sqrt{L}$$ and $(log2(L)+10)/10$ but that hasn't got me anywhere.

I am out of my depth. Please help.

Is it possible to re-arrange this equation to make v the subject?

$$L={v}^{2}.{2}^{10(v-1)}$$

If so, what is the answer?

If it helps (which by excluding zero it should)...

$$0<v<1$$

I have tried pages of scribbling and got nowhere. In desperation I have tried solving each product separately (easy enough), and then tried to get the right overall result from some combination of $$\sqrt{L}$$ and $(log2(L)+10)/10$ but that hasn't got me anywhere.

I am out of my depth. Please help.