The sum of 3 times Darlene's age and 7 times Sharon's is 173. Darlene is 2 years less than twice as old as Sharon is. How do you find each of their ages?

Cyrus Travis

Cyrus Travis

Answered question

2022-10-25

The sum of 3 times Darlene's age and 7 times Sharon's is 173. Darlene is 2 years less than twice as old as Sharon is. How do you find each of their ages?

Answer & Explanation

Adalyn Pitts

Adalyn Pitts

Beginner2022-10-26Added 15 answers

Let d be Darlene's age and s be Sharons's age.
We are given:
3d+7s=173
d=2s−2
Substitute this second equation into the first to get an equation in s:
173=3d+7s=3(2s−2)+7s=6s−6+7s=13s−6
Add 6 to both ends to get: 13s=173+6=179
Divide both ends by 13 to get: s = 179 13 = 13 10 13
Hence d = 2 s - 2 = 2 179 13 - 2 = 358 13 - 26 13 = 332 13 = 25 7 13
I suspect the 173 in the question should be 163, which would yield: s=13 and d=24.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?