Can someone help me out with this question about logs? please

$${3}^{2x}-{2}^{2y}=17$$

Find $x+y$

Here is what I did so far: Let $m={3}^{2x}$ and let $n={2}^{2y}$, $x=\frac{{\mathrm{log}}_{3}m}{2}$, $y=\frac{{\mathrm{log}}_{2}n}{2}$

$$x+y=\frac{{\mathrm{log}}_{3}m+{\mathrm{log}}_{2}n}{2}$$

x+y= (base(3)17+n)+(base(2)n)/2

don't know what to do from there

$${3}^{2x}-{2}^{2y}=17$$

Find $x+y$

Here is what I did so far: Let $m={3}^{2x}$ and let $n={2}^{2y}$, $x=\frac{{\mathrm{log}}_{3}m}{2}$, $y=\frac{{\mathrm{log}}_{2}n}{2}$

$$x+y=\frac{{\mathrm{log}}_{3}m+{\mathrm{log}}_{2}n}{2}$$

x+y= (base(3)17+n)+(base(2)n)/2

don't know what to do from there