Find the sum of a geometric sequence whose first term is -160, whose last (nth) term is 5, and whose common ratio is -1/2

Kevin Charles
2022-10-22
Answered

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Plutbantonavv

Answered 2022-10-23
Author has **15** answers

The numbers are

−160,80,−40,20,−10,5

and these numbers may be obtained by multiplying the 1st term by $r=-\frac{1}{2}$ and so forth and so on...

Add all the terms algebraically

Sum=−160+80−40+20−10+5=−105

Sum=−105

−160,80,−40,20,−10,5

and these numbers may be obtained by multiplying the 1st term by $r=-\frac{1}{2}$ and so forth and so on...

Add all the terms algebraically

Sum=−160+80−40+20−10+5=−105

Sum=−105

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