How to compute the inverse laplace transform of this term? (-3/(10)s−1/5)/((s+1)^2+1)

Francis Oliver 2022-10-22 Answered
How to compute the inverse laplace transform of this term? 3 10 s 1 5 ( s + 1 ) 2 + 1
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Answers (2)

indivisast7
Answered 2022-10-23 Author has 13 answers
L ( y ) = 3 10 s 1 5 ( s + 1 ) 2 + 1
you want to get this into the form. a ( s + 1 ) + b ( s + 1 ) 2 + 1
At which point:
y = a e t cos t + b e t sin t
3 10 ( s + 1 ) + 1 10 ( s + 1 ) 2 + 1
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caritatsjq
Answered 2022-10-24 Author has 3 answers
Hint. One may write
3 10 s 1 5 ( s + 1 ) 2 + 1 = 3 10 ( s + 1 ) ( s + 1 ) 2 + 1 + 1 10 1 ( s + 1 ) 2 + 1
then one may apply the properties of the inverse Laplace transform to each term
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