Distance between (9,2,0) and (8,6,2)?

Distance between (9,2,0) and (8,6,2)?
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Hilfeform5c
The distance formula for 3 dimensions is:
$\sqrt{{\left(\Delta x\right)}^{2}+{\left(\Delta y\right)}^{2}+{\left(\Delta z\right)}^{2}}$
In this case,
$\Delta x=8-9=-1$
$\Delta y=6-2=4$
$\Delta z=2-0=2$
So the distance is:
$\sqrt{{\left(-1\right)}^{2}+{4}^{2}+{2}^{2}}=\sqrt{1+16+4}=\sqrt{21}$