In the xy coordinate plane the slope of line p is 1/2 and its x-intercept is -3. How do you find the equation of a perpendicular to p and intersects p at is x-intercept.?

George Morales

George Morales

Answered question

2022-10-22

In the xy coordinate plane the slope of line p is 1/2 and its x-intercept is -3. How do you find the equation of a perpendicular to p and intersects p at is x-intercept.?

Answer & Explanation

Amadek6

Amadek6

Beginner2022-10-23Added 21 answers

The equation of a line having a slope m and passing through point ( x 1 , y 1 ) is ( y - y 1 ) = m ( x - x 1 ) . As the slope of line is 1 2 and its x-intercept is −3 (i.e. it passes through (−3,0), its equation is
( y - 0 ) = 1 2 ( x - ( - 3 ) ) or y = 1 2 x + 3 2 i.e. x - 2 y + 3 = 0 .
As the slope of line p is 1 2 , slope of line perpendicular to it is ( - 1 ) ÷ 1 2 = - 1 × 2 = - 2 and as it intersects p at its x-intercept, it tpp passes through (−3,0) and its equation will be
(y−0)=−2(x−(−3)) or y=−2x−6 i.e. 2x+y+6=0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?