In the process of running through an algorithm, I have derived the following systems of equations: i) 1/3+1/3x_1+1/3x_6=x_5, ii) 1/2+1/4x_6=x1, iii) 1/2+1/2x_5=x_6

Ryder Ferguson 2022-10-20 Answered
In the process of running through an algorithm, I have derived the following systems of equations:
i) 1 / 3 + 1 / 3 x 1 + 1 / 3 x 6 = x 5
ii) 1 / 2 + 1 / 4 x 6 = x 1
iii) 1 / 2 + 1 / 2 x 5 = x 6
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Answers (1)

Lintynx
Answered 2022-10-21 Author has 11 answers
we ca write
1 + x 1 + x 6 = 3 x 5
2 + x 6 = 4 x 1
1 + x 5 = 2 x 6
with x 5 = 2 x 6 1 we get
x 1 5 x 6 = 4
and with
x 6 = 4 x 1 2
we obtain
x 1 5 ( 4 x 1 2 ) = 4
thus we get
x 1 = 14 19
from here we can proceed.
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