# Find the slope of the line perpendicular to y=−4x/15+15

Find the slope of the line perpendicular to $y=-\frac{4}{15}x+15$
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Kenley Rasmussen
The slope of the given line is $m=-\frac{4}{15}$
The negative reciprocal: $m\prime =-\left(-\frac{15}{4}\right)=\frac{15}{4}$
So, the slope of the perpendicular line is $\frac{15}{4}$