Write an equation of a line passing through (2, 5), perpendicular to x−5y=−10

Kamila Frye 2022-10-16 Answered
Write an equation of a line passing through (2, 5), perpendicular to x−5y=−10
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Answers (1)

Kaylee Evans
Answered 2022-10-17 Author has 20 answers
Let's first look at the the line x−5y=−10 and solve it for y so that we can put it into the slope-intercept form, the general form of which is:
y=mx+b, where m= slope and b= y-intercept.
x - 5 y = - 10
5 y = x + 10
y = 1 5 x + 2
And so slope, m = 1 5
To find the perpendicular slope, we take the negative inverse, which gives us m=−5.
To find the line passing through the point (2,5) with slope −5, we can use the point slope form, which has as a general form:
y - y 1 = m ( x - x 1 ) where x 1 , y 1 are a point. So we have:
(y−5)=−5(x−2)
For comparison, let's put this into slope-intercept form:
y=−5x+15
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