Paola Mayer
2022-10-16
Answered

Given the one-to-one function $$r(x)=\frac{2}{x+5}$$ Write the inverse function in inverse function notation.

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Dana Simmons

Answered 2022-10-17
Author has **14** answers

$$r(x)=\frac{2}{x+5}\phantom{\rule{0ex}{0ex}}y=\frac{2}{x+5}\phantom{\rule{0ex}{0ex}}x+5=\frac{2}{y}\phantom{\rule{0ex}{0ex}}{r}^{-1}(x)=\frac{2}{x}-5\phantom{\rule{0ex}{0ex}}x\ne 0$$

So $$x\in (-\mathrm{\infty},0)\cup (0,\mathrm{\infty})$$

So $$x\in (-\mathrm{\infty},0)\cup (0,\mathrm{\infty})$$

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Each situation must be on a different graph.

1. Shifted to the left 4 units.

2.Shifted down 4 units.

3.Reflected about the x axise.

4.Horizontall stretched by a factor of 4.

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1. Shifted to the left 4 units.

2.Shifted down 4 units.

3.Reflected about the x axise.

4.Horizontall stretched by a factor of 4.

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Foreach of the following functions use the quadratic formula to find the zeros of f. Then, find the maximum or minimum value of f(x).

(a)$f(x)={x}^{2}-8x$

(b)$f(x)=-2{x}^{2}-9x+5$

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Suppose u and v are differentiable functions of x and that

u(1) = 2, u'(1) = 0, v(1) = 5, v'(1) = -1.

Find the values of the following derivatives at x = 1.

(d/dx)(uv)

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Find the values of the following derivatives at x = 1.

(d/dx)(uv)

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Does