Solve ${2}^{x}=13mod{3}^{4}$

I know $\mathrm{log}13=30mod{3}^{4}$ and $\mathrm{log}16=15mod{3}^{4}$

I've tried subbing $\mathrm{log}13/\mathrm{log}16$ for $2$ but I am not sure what to do next.

I know $\mathrm{log}13=30mod{3}^{4}$ and $\mathrm{log}16=15mod{3}^{4}$

I've tried subbing $\mathrm{log}13/\mathrm{log}16$ for $2$ but I am not sure what to do next.