I want to find the equation of line perpendicular to y=−5/3x−8 and passing through (−9,−3)

Christopher Saunders 2022-10-15 Answered
I want to find the equation of line perpendicular to y = - 5 3 x - 8 and passing through (−9,−3)
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Answers (1)

flasheadita237m
Answered 2022-10-16 Author has 17 answers
The two lines are perpendicular to each other, if the product of their slopes is −1. Hence if slope of one line is given as a b , slope of line perpendicular to it is - b a .
As equation of one line is given in slope-intercept form as y = - 5 3 x - 8 , its slope is - 5 3 .
Hence slope of line perpendicular to it is 3 5 .
Now equation of line passing through ( x 1 , y 1 ) and having slope m is ( y - y 1 ) = m ( x - x 1 )
Hence, equation of a line passing through (−9,−3) and having a slope 3 5 is
( y - ( - 3 ) ) = 3 5 ( x - ( - 9 ) )
or 5(y+3)=3(x+9)
or 5y+15=3x+27
or 3x−5y+12=0
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