How would you find the inverse Laplace transformation of (3s+4)/(s^2−16) when s>4?

How would you find the inverse Laplace transformation of $\frac{3s+4}{{s}^{2}-16}$ when s>4?
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Hint:
Write the partial fraction fraction expansion as:
$\begin{array}{}\text{(1)}& \frac{3s+4}{{s}^{2}-16}=\frac{1}{s+4}+\frac{2}{s-4}\end{array}$
Now, take the inverse Laplace of each of the terms on the right-hand-side (RHS) of (1).
We have for s>a:
${\mathcal{L}}^{-1}\left(\frac{1}{s-a}\right)={e}^{at}$