x^3+100<0

${x}^{3}+100<0$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

First you move 100 over
${x}^{3}<-100$
then you take the cube root to get rid of the cube. This is the same as
$x<-{100}^{\frac{1}{3}}$