# Find the slope of any line perpendicular to the line passing through (1,−2) and (−8,1)

Find the slope of any line perpendicular to the line passing through (1,−2) and (−8,1)
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The slope of the line passing through (1,-2) and (-8,1) is = $\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$ or $\frac{1+2}{-8-1}=-\frac{1}{3}$
So the slope of the perpendicular line is $-\frac{1}{-\frac{1}{3}}=3$. Since the condition of perpendicularity of two lines is product of their slopes will be equal to -1