How to solve for k when the area about the x axis and under the graph of the f(x)=1/x from interval x=[2,k] is equal to ln(4)?

caschaillo7 2022-10-17 Answered
How to solve for k when the area about the x axis and under the graph of the f ( x ) = 1 x from interval x = [ 2 , k ] is equal to ln ( 4 )?
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Answers (1)

Kaylee Evans
Answered 2022-10-18 Author has 20 answers
Notice
2 k 1 x d x = ln 4 = 2 ln 2
This is given. But
2 k 1 x d x = ln k ln 2
Hence,
ln k ln 2 = 2 ln 2 ln k = 3 ln 2 ln k = ln 2 3 k = 2 3 = 8
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