Center (-a,a) and radius 5a

beefypy
2022-10-15
Answered

Find an equation of the circle that satisfies the given conditions.

Center (-a,a) and radius 5a

Center (-a,a) and radius 5a

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megagoalai

Answered 2022-10-16
Author has **22** answers

General equation of circle with centre

1 radius $$\Rightarrow (x-a{)}^{2}+(y-t{)}^{2}={r}^{2}\phantom{\rule{0ex}{0ex}}\therefore (x-(-a{)}^{2}{)}^{2}+(y-a{)}^{2}=(5a{)}^{2}\phantom{\rule{0ex}{0ex}}(x+a{)}^{2}+(y-a{)}^{2}=25{a}^{2}$$

1 radius $$\Rightarrow (x-a{)}^{2}+(y-t{)}^{2}={r}^{2}\phantom{\rule{0ex}{0ex}}\therefore (x-(-a{)}^{2}{)}^{2}+(y-a{)}^{2}=(5a{)}^{2}\phantom{\rule{0ex}{0ex}}(x+a{)}^{2}+(y-a{)}^{2}=25{a}^{2}$$

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