In triangle XYZ, the bisector of $\mathrm{\angle}XYZ$ intersects $\overline{XZ}$ at E if $\frac{XY}{YZ}=\frac{3}{4}$ an $XZ=42$, find the greatest integer value of XY.

Thus far, I have determined that $XE=18$ and $ZE=24$ by the angle bisector theorem, but I am unsure how to find XY.

Thus far, I have determined that $XE=18$ and $ZE=24$ by the angle bisector theorem, but I am unsure how to find XY.