How would I go about finding a vector equation of a hyperplane

$3{x}_{1}+{x}_{2}-2{x}_{3}+4{x}_{4}=5$

I know I need to find 3 vectors and another vector that shifts from the origin in the form

$r\overrightarrow{a}+s\overrightarrow{b}+t\overrightarrow{c}+\overrightarrow{d}$

$3{x}_{1}+{x}_{2}-2{x}_{3}+4{x}_{4}=5$

I know I need to find 3 vectors and another vector that shifts from the origin in the form

$r\overrightarrow{a}+s\overrightarrow{b}+t\overrightarrow{c}+\overrightarrow{d}$