How would I go about finding a vector equation of a hyperplane 3x_1+x_2−2x_3+4x_4=5

miklintisyt 2022-10-16 Answered
How would I go about finding a vector equation of a hyperplane
3 x 1 + x 2 2 x 3 + 4 x 4 = 5
I know I need to find 3 vectors and another vector that shifts from the origin in the form
r a + s b + t c + d
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Answers (1)

SoroAlcommai9
Answered 2022-10-17 Author has 13 answers
Hint: Take x 1 , x 3 , x 4 to be free variables. Then,
x 1 = x 1
x 2 = 5 3 x 1 + 2 x 3 4 x 4
x 3 = x 3
x 4 = x 4
Now write this in vector notation.
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