What is the Maclaurin series of z^3sin(z^2)

Ryder Ferguson 2022-10-14 Answered
What is the Maclaurin series of
z 3 sin ( z 2 )
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Answers (1)

Kenley Rasmussen
Answered 2022-10-15 Author has 13 answers
Recall that
sin ( z ) = n = 0 ( 1 ) n z 2 n + 1 ( 2 n + 1 ) !
Thus,
sin ( z 2 ) = n = 0 ( 1 ) n z 4 n + 2 ( 2 n + 1 ) !
and finally
z 3 sin ( z 2 ) = n = 0 ( 1 ) n z 4 n + 5 ( 2 n + 1 ) !
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