The distance shown on a map is 1/500 of the actual distance. If the distance shown on map is 1/5 foot, how long is the actual distance in feet?

Payton George
2022-10-12
Answered

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veirenca77

Answered 2022-10-13
Author has **9** answers

The distance shown on the map= 1/5 feet.

Let, the actual distance= x feet.

By the problem, the distance shown on a map is 1/500 of the actual distance.

So,

$$x\times \frac{1}{500}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{x}{500}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}\Rightarrow x=\frac{1}{5}\times 500\phantom{\rule{0ex}{0ex}}\Rightarrow x=100$$

So, the actual distance = 100 feet.

Let, the actual distance= x feet.

By the problem, the distance shown on a map is 1/500 of the actual distance.

So,

$$x\times \frac{1}{500}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{x}{500}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}\Rightarrow x=\frac{1}{5}\times 500\phantom{\rule{0ex}{0ex}}\Rightarrow x=100$$

So, the actual distance = 100 feet.

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