$$10xy-2xy+45x-9w$$

Eliza Gregory
2022-10-13
Answered

Factor by the method of grouping. Show the check by re-multiplication of the factors.

$$10xy-2xy+45x-9w$$

$$10xy-2xy+45x-9w$$

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Adenomacu

Answered 2022-10-14
Author has **13** answers

Given equation is

$$10xy-2xy+45x-9w$$

Above equation rewritten as

$$10xy+45x-2xy-9x=5x(2y+9)-x(2y+9)\phantom{\rule{0ex}{0ex}}=(5x-x)(2y-9)\phantom{\rule{0ex}{0ex}}=4x(2y+9)$$

Factors are $$5x-x,\text{}2y+9$$

Or, $$4x,\text{}2y+9$$

So, we get

$$10xy-2xy+45x-9x=8xy+36x$$

Multiply the factors (4x) and (2y+9) we get

$$(4x)(2y+9)=4x\times 2y+4x\times 9\phantom{\rule{0ex}{0ex}}=8xy+36x$$

Then, we check multiplication of factors

Factors are 4x, 2y+9

$$10xy-2xy+45x-9w$$

Above equation rewritten as

$$10xy+45x-2xy-9x=5x(2y+9)-x(2y+9)\phantom{\rule{0ex}{0ex}}=(5x-x)(2y-9)\phantom{\rule{0ex}{0ex}}=4x(2y+9)$$

Factors are $$5x-x,\text{}2y+9$$

Or, $$4x,\text{}2y+9$$

So, we get

$$10xy-2xy+45x-9x=8xy+36x$$

Multiply the factors (4x) and (2y+9) we get

$$(4x)(2y+9)=4x\times 2y+4x\times 9\phantom{\rule{0ex}{0ex}}=8xy+36x$$

Then, we check multiplication of factors

Factors are 4x, 2y+9

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