# Write the equation of line passes through (-4,-3), and is perpendicular to 4x + y=7

Write the equation of line passes through (-4,-3), and is perpendicular to 4x + y=7
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Crubery3
Equation of a line that is perpendicular to Ax+By=C
is of the form Bx−Ay=k i.e. reversing te coefficients of x and y and changing sign of one of them.
Hence, the line perpendicular to 4x+y=7 has equation of the form
x−4y=k and as it passes through (−4,−3)
we should have $\left(-4\right)-4×\left(-3\right)=k$
and therefore k=−4+12=8
and desired equation is x−4y=8 or 3x−y+14=0