Is this true: inverse Laplace transform of exp(−s)F(s)=(t−1)u(t−1)u(t−1)

Iris Vaughn 2022-10-12 Answered
y ( s ) = 1 / s 1 / s 2 + exp ( s ) ( 1 / s 2 )
I'm struggling with
exp ( s ) ( 1 / s 2 )
formulas:
f ( t 1 ) u ( t 1 ) exp ( s ) F ( s )
But
f ( t ) = t u ( t )
is this true: inverse Laplace transform of
exp ( s ) F ( s ) = ( t 1 ) u ( t 1 ) u ( t 1 )
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Answers (1)

flasheadita237m
Answered 2022-10-13 Author has 17 answers
It's simply:
L 1 ( e s 1 s 2 ) = u ( t 1 ) ( t 1 )
Since you have that:
L 1 ( e c s F ( s ) ) = u ( t c ) f ( t c )
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