# Find the equation of the line perpendicular to y=13x that passes through (7,8)

Find the equation of the line perpendicular to y=13x that passes through (7,8)
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Since the line is perpendicular to another line with slope 13, its slope will be 13's opposite reciprocal, or $-\frac{1}{13}$. So the line we are trying to find has the equation $y=-\frac{1}{13}x+b$. Since it passes through (7,8), it holds that $8=-\frac{7}{13}+b⇒b=111$.
So the final equation is $y=-\frac{1}{13}x+111$