# Find the slope of any line perpendicular to the line passing through (−9,8) and (0,0)

Find the slope of any line perpendicular to the line passing through (−9,8) and (0,0)
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Martha Dickson
m = $\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}$
m = $\frac{0-8}{0-\left(-9\right)}$
m = $-\frac{8}{9}$
The slope of a line perpendicular to that line would be the negative reciprocal. To find this, invert the numerator and the denominator and multiply by -1, which gives you m = $\frac{9}{8}$
So, the slope of any line perpendicular to the line passing through (-9, 8) and (0,0) is $\frac{9}{8}$