Geographical Analysis (Jan, 2010) presented a study of Emergency Medical Services (EMS) ability to meet the demand for an ambulance. In one example, t

aflacatn

aflacatn

Answered question

2021-01-02

Geographical Analysis (Jan, 2010) presented a study of Emergency Medical Services (EMS) ability to meet the demand for an ambulance. In one example, the researchers presented the following scenario. An ambulance station has one vehicle and two demand locations, A and B. The probability that the ambulance can travel to a location in under eight minutes is .58 for location A and .42 for location B. The probability that the ambulance is busy at any point in time is .3. a. Find the probability that EMS can meet demand for an ambulance at location A. b. Find the probability that EMS can meet demand for an ambulance at location B.

Answer & Explanation

Roosevelt Houghton

Roosevelt Houghton

Skilled2021-01-03Added 106 answers

Let C denote the event that the ambulance is busy. Then P(C)=0.3 and P(Cc)=0.7. Let A denote the event that EMS can meet demand at location A, and let A denote the event that EMS can meet demand at location B.
We must find P(A), which we can write as P(A)=P(AC)P(C)+P(ACc)P(Cc)
If C happened, then P(A|C)=0. On the other hand, P(ACc)=0.58, so P(A)=0+0.580.7=0.406
We must find P(B), which we can write as P(B)=P(BC)P(C)+P(BCc)P(Cc)
If C happened, then P(B|C)=0. On the other hand, P(BCc)=0.42, so P(A)=0+0.420.7=0.294

Do you have a similar question?

Recalculate according to your conditions!

New Questions in High school probability

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?