Let C be the event that someone has visited Canada, and M be the event that someone has visited Mexico.

We need to find \(\displaystyle{P}{\left({C}{\mid}{M}\right)}\). By definition, \(\displaystyle{P}{\left({C}{\mid}{M}\right)}=\frac{{{P}{\left({C}⋂{M}\right)}}}{{P}}{\left({M}\right)}=\frac{{0.04}}{{0.09}}=\frac{{4}}{{9}}\sim{44.44}\%\)

If they were disjoint, we would have \(\displaystyle{P}{\left({C}⋂{M}\right)}={0}\frac{=}{{0.04}}\)

Therefore, they are not disjoint.

They are independent if and only if \(\displaystyle{P}{\left({C}⋂{M}\right)}={P}{\left({C}\right)}{P}{\left({M}\right)}\)

However, \(\displaystyle{P}{\left({C}⋂{M}\right)}={0.04}\)

\(\displaystyle{P}{\left({C}\right)}{P}{\left({M}\right)}={0.18}\cdot{0.09}={0.0162}\)

Therefore, \(\displaystyle{P}{\left({C}⋂{M}\right)}\frac{=}{{P}}{\left({C}\right)}{P}{\left({M}\right)}\)

so C and M are not independent.

We need to find \(\displaystyle{P}{\left({C}{\mid}{M}\right)}\). By definition, \(\displaystyle{P}{\left({C}{\mid}{M}\right)}=\frac{{{P}{\left({C}⋂{M}\right)}}}{{P}}{\left({M}\right)}=\frac{{0.04}}{{0.09}}=\frac{{4}}{{9}}\sim{44.44}\%\)

If they were disjoint, we would have \(\displaystyle{P}{\left({C}⋂{M}\right)}={0}\frac{=}{{0.04}}\)

Therefore, they are not disjoint.

They are independent if and only if \(\displaystyle{P}{\left({C}⋂{M}\right)}={P}{\left({C}\right)}{P}{\left({M}\right)}\)

However, \(\displaystyle{P}{\left({C}⋂{M}\right)}={0.04}\)

\(\displaystyle{P}{\left({C}\right)}{P}{\left({M}\right)}={0.18}\cdot{0.09}={0.0162}\)

Therefore, \(\displaystyle{P}{\left({C}⋂{M}\right)}\frac{=}{{P}}{\left({C}\right)}{P}{\left({M}\right)}\)

so C and M are not independent.