# What is the permutation formula for P(12,8)? 12! 8!/12! 12!/(12-8)! 12!/ 8!

What is the permutation formula for P(12,8)?
$a.12!\phantom{\rule{0ex}{0ex}}b.\frac{8!}{12!}\phantom{\rule{0ex}{0ex}}c.\frac{12!}{\left(12-8\right)!}\phantom{\rule{0ex}{0ex}}d.\frac{12!}{8!}$
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xgirlrogueim
We know that, permutation formula is
$P\left(n,r\right)=nPr\phantom{\rule{0ex}{0ex}}nPr=\frac{n!}{\left(n-r\right)!}$
where, nPr=permutation
n=Total number of object.
r=number of selected objects
$\therefore P\left(12,8\right)=12{P}_{8}\phantom{\rule{0ex}{0ex}}\therefore P\left(12,8\right)=\frac{12!}{\left(12-8\right)!}$
option (c) $P\left(12,8\right)=\frac{12!}{\left(12-8\right)!}$ is correct