priscillianaw1

2022-09-06

I have used the quotient rule and chain rule to solve for ${0.6}^{x}$ but its still wrong.
$P\left(x\right)=\frac{1864}{1+49×\left(0.6{\right)}^{x}}$

Do you have a similar question?

falwsay

Expert

we have after simplifications
${P}^{\prime }\left(x\right)=-91336\phantom{\rule{thinmathspace}{0ex}}\frac{{\left(3/5\right)}^{x}\mathrm{ln}\left(3/5\right)}{{\left(1+49\phantom{\rule{thinmathspace}{0ex}}{\left(3/5\right)}^{x}\right)}^{2}}$

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