Given:

32 cards in total

16 yellow cards

16 brown cards

First 6 drawn cards: yellow, brown, yellow, yellow, brown

Since 6 of the 32 cards were already drawn, there are \(32-6=26\) cards remaining.

# of possible outcomes \(= 26\)

The set of cards contains 16 yellow cards, while 4 of the yellow cards were already drawn and thus there are \(16-4=12\) yellow cards remaining that we can select on the next draw:

# of favorable outcomes \(= 12\)

The probability is the number of favorable outcomes divided by the number of possible outcomes

P(Next card is yellow)= # of favorable outcomes # of possible outcomes=\(\displaystyle\frac{{12}}{{26}}=\frac{{6}}{{13}}\sim{0.4615}={46.15}\%\)