Given:

Probability rain San Francisco= \(\displaystyle\frac{{1}}{{6}}\)

Probability rain Miami = \(\displaystyle\frac{{5}}{{6}}\)

Let us consider a blue and red number cube. The blue number cube will represent San Francisco and the red number cube will represent Miami.

A number cube has 6 possible outcomes: 1, 2, 3, 4, 5,6.

The probability of rain in San Franciscois then simulated by the blue number cube, when exactly 1 of the 6 possible outcomes on the blue number cube correspond with rain (while the other outcomes correspond with no rain) as the probability of rain needs to be 1/6.

Let Blue 1=rain in San Francisco and Blue 2, 3, 4, 5, 6=no rain in San Francisco.

The probability of rain in Miami is then simulated by the red number cube, when exactly 5 of the 6 possible outcomes on the red number cuthe correspond with rain (while the other outcome corresponds with no rain) as the probability of rain needs to be 5/6.

Tet Red 1=no rain it Miami and Red 2, 3, 4, 5, 6 = rain in Miami

Probability rain San Francisco= \(\displaystyle\frac{{1}}{{6}}\)

Probability rain Miami = \(\displaystyle\frac{{5}}{{6}}\)

Let us consider a blue and red number cube. The blue number cube will represent San Francisco and the red number cube will represent Miami.

A number cube has 6 possible outcomes: 1, 2, 3, 4, 5,6.

The probability of rain in San Franciscois then simulated by the blue number cube, when exactly 1 of the 6 possible outcomes on the blue number cube correspond with rain (while the other outcomes correspond with no rain) as the probability of rain needs to be 1/6.

Let Blue 1=rain in San Francisco and Blue 2, 3, 4, 5, 6=no rain in San Francisco.

The probability of rain in Miami is then simulated by the red number cube, when exactly 5 of the 6 possible outcomes on the red number cuthe correspond with rain (while the other outcome corresponds with no rain) as the probability of rain needs to be 5/6.

Tet Red 1=no rain it Miami and Red 2, 3, 4, 5, 6 = rain in Miami