$$\sqrt{3}\mathrm{sin}x-\mathrm{cos}x=\sqrt{2}$$

I think to do :

$$\frac{(\sqrt{3}\mathrm{sin}x-\mathrm{cos}x=\sqrt{2})}{\sqrt{2}}$$

but i dont get anything. Or to divied by $\sqrt{3}$ :

$$\frac{(\sqrt{3}\mathrm{sin}x-\mathrm{cos}x=\sqrt{2})}{\sqrt{3}}$$

I think to do :

$$\frac{(\sqrt{3}\mathrm{sin}x-\mathrm{cos}x=\sqrt{2})}{\sqrt{2}}$$

but i dont get anything. Or to divied by $\sqrt{3}$ :

$$\frac{(\sqrt{3}\mathrm{sin}x-\mathrm{cos}x=\sqrt{2})}{\sqrt{3}}$$