# The population of a city t years from now is given by <math xmlns="http://www.w3.org/1998/Math/MathML" display="block"> <mi>P</mi> <mo>=</mo> <mn>250000</mn> <msup> <mi>e</mi> <mrow class="MJX-TeXAtom-ORD"> <mn>0.04</mn> <mi>t</mi> </mrow> </msup> [/itex]

The population of a city t years now is given by
$P=250000{e}^{0.04t}$
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Jane Reese
Solved;
$P=250000{e}^{0.04t}$
Derivative of $P=250000{e}^{0.04t}$
Derivative of $⇒0.4\left(250000\right)\phantom{\rule{0ex}{0ex}}⇒0.4\left(250000\right){e}^{0.4t}\phantom{\rule{0ex}{0ex}}⇒0.04\left(25000\right){e}^{0.04\left(3\right)}\right)\phantom{\rule{0ex}{0ex}}⇒0.04\left(25000\right){e}^{0.12}\phantom{\rule{0ex}{0ex}}⇒11274.96$
or 11275 people per year