What is the laplace transform of $(\delta (t-\pi /6))u(t-\pi /6)$

I know that $L(f(t-a).u(t-a))={e}^{-as}.F(s)$

Does that mean the laplace transform of the above equation is ${e}^{-2\pi s}$?

I know that $L(f(t-a).u(t-a))={e}^{-as}.F(s)$

Does that mean the laplace transform of the above equation is ${e}^{-2\pi s}$?