FInd the integers if the sum of three consecutive even integers is 66

st3he1d0t

st3he1d0t

Answered question

2022-09-05

FInd the integers if the sum of three consecutive even integers is 66

Answer & Explanation

Matthew Benton

Matthew Benton

Beginner2022-09-06Added 9 answers

You have to 'jump' an odd number to get to the next even number. So even numbers occur every second place (counting in 2's)
Set the first even number as n
Then the second is n+2
The third is n+4
Subtract 6 from both sides
3n=60
Divide both sides by 3
n=20
So the three numbers are: 20;22;24
Kwenze0l

Kwenze0l

Beginner2022-09-07Added 2 answers

Take the first integer as x. Since we are talking about the next even integer, it will come when you add two to x.
For example, let's say that you have 2 as the value of x. The next even integer is 4, which is x+2, and the next is 6, which is x+4.
So eventually, the equation is
(x)+(x+2)+(x+4)=66
3x+6=66
3x=66−6
3x=60
x=60/3
x=20
So
x=20
x+2=22
x+4=24

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