The base of a triangle of a given area varies inversely as the height. A triangle has a base of 18cm and a height of 10cm. Find the height of a triangle of equal area and with base 15cm

bolton8l
2022-10-08
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Nadia Berry

Answered 2022-10-09
Author has **7** answers

The area of a triangle can be determined with the equation $area=\frac{1}{2}\cdot base\cdot height$

Find the area of the first triangle, by substituting the measurements of the triangle into the equation.

$Area\u25b3=\frac{1}{2}\cdot 18\cdot 10$

$=90c{m}^{2}$

Let the height of the second triangle =x.

So the area equation for the second triangle $=\frac{1}{2}\cdot 15\cdot x$

Since the areas are equal,

$90=\frac{1}{2}\cdot 15\cdot x$

Times both sides by 2.

180=15x

x=12

Find the area of the first triangle, by substituting the measurements of the triangle into the equation.

$Area\u25b3=\frac{1}{2}\cdot 18\cdot 10$

$=90c{m}^{2}$

Let the height of the second triangle =x.

So the area equation for the second triangle $=\frac{1}{2}\cdot 15\cdot x$

Since the areas are equal,

$90=\frac{1}{2}\cdot 15\cdot x$

Times both sides by 2.

180=15x

x=12

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