Dree rolls a strike in 6 out of the 10 frames of bowling. What is the experimental probability that Dree will roll a strike in the first frame of the next game? Explain why a number cube would not be a good way to simulate this situation.

Question
Dree rolls a strike in 6 out of the 10 frames of bowling. What is the experimental probability that Dree will roll a strike in the first frame of the next game? Explain why a number cube would not be a good way to simulate this situation.

Answers (1)

2020-12-18
There were 10 frames bowled and thus there are 10 possible outcomes.
# of possible outcomes = 10
6 strikes were rolled and thus there are 6 favorable outcomes.
# of favorable outcomes = 6
The probability is the number of favorable outcomes divided by the number of possible outcomes:
P(strike)= #of favorable outcomes/# of possible outcomes=\(\displaystyle\frac{{6}}{{10}}=\frac{{3}}{{5}}={0.6}={60}\%\)
We note that the denominator of the probability is 5, which means that the number of possible outcomes in a simulation would need to be a. multiple of 5.
P(strike) = = : =06 = 60%
However, a number cube has 6 possible outcomes (1, 2, 3, 4, 5, 6) and 6 is not a multiple of 5, thus a number cube will not be a good way to simulation.
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