# Find the equation of the line that passes through the point (0,2) and perpendicular to the line x-y=6

Find the equation of the line that passes through the point (0,2) and perpendicular to the line x-y=6
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Rihanna Blanchard
Let,the equation of the line be y=mx+c where, m is the slope and c is the Y intercept.
now,slope of the equation x−y=6 or y=x−6 is 1
We know that for two lines to be mutually perpendicular,their product of slope will have to be −1
So,m*1=−1
or, m=−1
So,the equation becomes, y=−x+c
Now,given the line passes through (0,2)
So,putting the values we get,
2=0+c
So,the equation of the line is, y=−x+2
or, x+y=2