What is the probability of obtain tails and an odd number?

Ava-May Nelson
2020-10-20
Answered

What is the probability of obtain tails and an odd number?

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Laaibah Pitt

Answered 2020-10-21
Author has **98** answers

The coin has 2 possible outcomes: heads H and tails T/
The die has 6 possible outcomes: 1, 2, 3, 4, 5, 6.

There are then$2\cdot 6=12$ possible outcomes of flipping the coin and rolling the die: H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6.

# of possible outcomes = 12

We note that 3 of the 12 possible outcomes result in tails and an odd number: T1, 73, T5.

# of favorable outcomes = 3

The probability is the number of favorable outcomes divided by the number of possible outcomes:

P(tails and odd) = # of favorable outcomes /# of possible outcomes Te hie outcomes >$=\frac{3}{12}=\frac{1}{4}=0.25=25\mathrm{\%}$

There are then

# of possible outcomes = 12

We note that 3 of the 12 possible outcomes result in tails and an odd number: T1, 73, T5.

# of favorable outcomes = 3

The probability is the number of favorable outcomes divided by the number of possible outcomes:

P(tails and odd) = # of favorable outcomes /# of possible outcomes Te hie outcomes >

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The problem reads: Suppose $P\left({X}_{1}\right)=.75$ and $P\left({Y}_{2}\mid {X}_{1}\right)=.40$ . What is the joint probability of $X}_{1$ and $Y}_{2$ ?

This is how I answered it. P($X}_{1$ and $Y}_{2$ ) $=P\left({X}_{1}\right)\times P\left({Y}_{1}\mid {X}_{1}\right)=.75\times .40=0.3.$

What I don't understand is how do you get the$P\left({Y}_{1}\mid {X}_{1}\right)$ ? I am totally new to Statistices and I need to understand each part of the process in order to get the whole concept. Can anyone help me to understand why the P and X exist and what they represent?

This is how I answered it. P(

What I don't understand is how do you get the