Given the following vectors $A=2i+3j+k$ and $B=4i+2j-k$, find ${I}_{A}\times {I}_{B}$, where ${I}_{A}$ is the unit vector in the direction of vector $A$ while ${I}_{B}$ is the unit vector in the direction of vector B.

omvamen71
2022-10-05
Answered

Given the following vectors $A=2i+3j+k$ and $B=4i+2j-k$, find ${I}_{A}\times {I}_{B}$, where ${I}_{A}$ is the unit vector in the direction of vector $A$ while ${I}_{B}$ is the unit vector in the direction of vector B.

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Jordan Owen

Answered 2022-10-06
Author has **7** answers

To get the unit vector in the direction of $\overrightarrow{v}$ , just multiply by the scalar $\frac{1}{|\overrightarrow{v}|}$, where $|\overrightarrow{v}|=\sqrt{{v}_{1}^{2}+{v}_{2}^{2}+{v}_{3}^{2}}$

So, for instance, $IA=\frac{1}{\sqrt{14}}\cdot (2i+3j+k)$

So, for instance, $IA=\frac{1}{\sqrt{14}}\cdot (2i+3j+k)$

Ariel Wilkinson

Answered 2022-10-07
Author has **1** answers

Vector A= unit vector of A* magnitude of A Similar is for vector B. Then take the cross product of Ia X Ib where Ia is unit vector of A and Ib is unit vector of B. You should be getting your answer in terms of Ic

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