Given the following vectors A=2i+3j+k and B=4i+2j−k, find I_A xx I_B, where I_A is the unit vector in the direction of vector A while I_B is the unit vector in the direction of vector B.

Given the following vectors $A=2i+3j+k$ and $B=4i+2j-k$, find ${I}_{A}×{I}_{B}$, where ${I}_{A}$ is the unit vector in the direction of vector $A$ while ${I}_{B}$ is the unit vector in the direction of vector B.
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Jordan Owen
To get the unit vector in the direction of $\stackrel{\to }{v}$ , just multiply by the scalar $\frac{1}{|\stackrel{\to }{v}|}$, where $|\stackrel{\to }{v}|=\sqrt{{v}_{1}^{2}+{v}_{2}^{2}+{v}_{3}^{2}}$
So, for instance, $IA=\frac{1}{\sqrt{14}}\cdot \left(2i+3j+k\right)$
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Ariel Wilkinson
Vector A= unit vector of A* magnitude of A Similar is for vector B. Then take the cross product of Ia X Ib where Ia is unit vector of A and Ib is unit vector of B. You should be getting your answer in terms of Ic