A car leaves an airport going 84 km/hr. 5 hours later, an airplane going 705 km/hr departs. How do you find the distance when the airplane will catch up with the car?

Janiah Parks 2022-09-04 Answered
A car leaves an airport going 84 km/hr. 5 hours later, an airplane going 705 km/hr departs. How do you find the distance when the airplane will catch up with the car?
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (1)

aveanoon
Answered 2022-09-05 Author has 8 answers
Call the distance you need d = x f - x i and the time the airplane needs T.
In general velocity will be v = x f - x i t
if x i = 0 (the airport, for both) we can write:
x f = v t (1)

so for the car and airplane x f has to be the same; so:
x f c a r = x f a i r

The cat will travel 5+T hours and the airplane T hours:
84 ( 5 + T ) = 705 T
425 + 84 T = 705 T
T = 425 621 = 0.684 h
using this into the expression for, say, the car we get:

x f = 84 ( 5 + T ) = 477.5 k m

The only thing is that you are given velocities without considering that the car and the airplane has to start from zero and accelerate...the passengers probably would not survive going from zero to 705km/hr instantly!
Did you like this example?
Subscribe for all access

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more