Magnetic Force of a current carrying wire loop on a magnetic object let's say we have a current carrying wire loop WITHOUT AN EXTERNAL MAGNETIC FIELD. It produces a magnetic field on its own. what would the magnetic field and force of this loop on a charge or a magnetic object(or whatever) outside the loop? I always find the equation of F = IBL which is the force on the on loop from an external magnetic field but i can never find the force that the loop itself produces. Like i am trying to calculate the force from the loop on an iron ball or find the magnetic field produced by just the loop but outside the loop. If i can get the magnetic field outside the loop then i can derive the force that i need using F = Del(m X B).

gsragator9 2022-09-01 Answered
Magnetic Force of a current carrying wire loop on a magnetic object
let's say we have a current carrying wire loop WITHOUT AN EXTERNAL MAGNETIC FIELD. It produces a magnetic field on its own. what would the magnetic field and force of this loop on a charge or a magnetic object(or whatever) outside the loop?
I always find the equation of F = IBL which is the force on the on loop from an external magnetic field but i can never find the force that the loop itself produces.
Like i am trying to calculate the force from the loop on an iron ball or find the magnetic field produced by just the loop but outside the loop. If i can get the magnetic field outside the loop then i can derive the force that i need using F = Del(m X B).
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (2)

Zara Pratt
Answered 2022-09-02 Author has 12 answers
Magnetic force is experienced by moving electric charges. You need find out the magnetic field produced by that ring or that current carrying object at a point in space and then use the formula F = q v × B
Did you like this example?
Subscribe for all access
omvamen71
Answered 2022-09-03 Author has 1 answers
well its the same case as in electrostatics. a point charge kept isolated can never feel the force due to its own electric field. like same way ANY source of a field can never be influenced by its own field. also recall that a value of magnetostat ic field diverges at its own location.(appears singularity)
Did you like this example?
Subscribe for all access

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

You might be interested in

asked 2021-02-19

 
Two snowcats tow a housing unit to a new location at McMurdo Base, Antarctica, as shown in the figure. The sum of the forces FA and FB exerted on the unit by the horizontal cables is parallel to the line L, and FA=4200 N. Determine FB? Determine the magnitude of FA+FB?

asked 2021-02-25

A stream of water strikes a stationary turbine bladehorizontally, as the drawing illustrates. The incident water streamhas a velocity of +18.0 m/s, while the exiting water stream has avelocity of -18.0 m/s. The mass of water per second that strikesthe blade is 17.0 kg/s. Find themagnitude of the average force exerted on the water by theblade.

asked 2021-02-11

Resolve the force F2 into components acting along the u and v axes and determine the magnitudes of the components.
image

asked 2021-01-06

A marble moves along the x-axis. The potential-energy functionis shown in Fig. 1
a) At which of the labeled x-coordinates is the force on the marble zero?
b) Which of the labeled x-coordinates is a position of stable equilibrium?
c) Which of the labeled x-coordinates is a position of unstable equilibrium?
image

asked 2022-04-06
Mysterious magnetic force!
If you have a loop in which current goes clockwise as seen from top, then it forms a north pole if seen from below. Now if a particle with positive charge goes from left to right under it, it experiences and upward force, now if the 1st loop was very large and particle goes from near about the axis of loop, it goes in a circle in anti-clockwise direction as seen from the top. This again generates a north pole if seen from top.
Q1. Since we have two north poles facing each other, why don't we get a new repulsive magnetic force?
If you closely observe this systen then the negative charges travelling in 1st loop in anti-clockwise direction have synchronized with the positive charge going anti-clockwise below it. Not only this, if you send the particle from right to left, it experiences a downward force and again synchronizes, now again if you try sending negative particles they get synchronized in the same way with the positive particles.
Q2. Why is such a synchronizing taking place?
I am more interested in the first question for now, as I am trying to work out the second problem myself.
asked 2022-07-23
What is the correct frame of reference for determining the magnetic force on a charge?
If two charges are both stationary in a given inertial frame, F1, then neither charge should experience a magnetic force due to the presence of the other charge (qv = 0). If we accelerate one charge, but not the other, then again, neither charge should experience a magnetic force, since only one charge has a non-zero velocity as measured in that inertial frame, meaning the other, stationary charge will experience no force in the magnetic field of the moving charge.
Now imagine that we are riding along as part of another inertial frame, F2, and that the first inertial frame discussed above that contains the two electrons F1, is traveling at a relative velocity of v from our perspective (i.e., it’s moving faster than us). Now imagine that we fire two electrons from our inertial frame F2, towards F1, one that travels at a velocity of v from our perspective, thereby traveling at the same velocity as the electron that appeared stationary in F1, and another that travels at the same velocity as the second, "faster" electron.
From our perspective in F2, both electrons have a non-zero velocity: the “slow one” traveling at a velocity of v, and the “fast one” traveling a bit faster than that. From our perspective, in F2, both electrons should experience a magnetic force of attraction due to their non-zero velocities in non-zero magnetic fields, which would change the path of those electrons from the perspective of both inertial frames.
However, from the perspective of F1, the “slow” electron is stationary, and should not experience any magnetic force in any magnetic field.
This seems to not make sense - what would happen as an experimental matter?
asked 2021-02-05

Two adults and a child want to push a wheeled cart in thedirection marked x in Fig. 4.29 The two adults push with horizontalforces F1 and F2 as shown in the figure. (a)Find the magnitude and direction of the smallest force that thechild should exerts the minimum force found in part (a), the cartaccelerates at 2.0 ms2 in the +x direction. What is theweight of the cart?